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剑指office(十七)树的子结构

 ·  ☕ 1 分钟  ·  🎅 YSL

题目描述

输入两棵二叉树A,B,判断B是不是A的子结构。(ps:我们约定空树不是任意一个树的子结构)

示例1

输入

{8,8,#,9,#,2,#,5},{8,9,#,2}

返回值

true
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/*
struct TreeNode {
	int val;
	struct TreeNode *left;
	struct TreeNode *right;
	TreeNode(int x) :
			val(x), left(NULL), right(NULL) {
	}
};*/
class Solution {
public:
    bool HasSubtree(TreeNode* pRoot1, TreeNode* pRoot2) {
        bool result = false;
        if(pRoot1!=NULL&&pRoot2!=NULL)
        {
            if(pRoot1->val==pRoot2->val)
                result = isSame(pRoot1,pRoot2);
            if(!result)
                result = HasSubtree(pRoot1->left, pRoot2);
            if(!result)
                result = HasSubtree(pRoot1->right, pRoot2);
        }
        return result;
    }
    bool isSame(TreeNode* pRoot1,TreeNode* pRoot2)
    {
        if(pRoot2==NULL)
            return true;
        if(pRoot1==NULL)
            return false;
        if(pRoot1->val!=pRoot2->val)
            return false;
        else
            return isSame(pRoot1->left, pRoot2->left)&&isSame(pRoot1->right, pRoot2->right);
    }
};